ExamPrepWay
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Solve this faster with the right shortcut first
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
Question Locked
Unlock full topic access, detailed explanations, and premium practice support.
Upgrade to continueCorrect answer and explanation unlock after the free practice limit.
Upgrade to continueShort Explanation
PremiumShort solution is premium content.
Upgrade to continueDetailed Explanation
Correct Answer:
Method / Topic: Organic Chemistry
Deprotonation produces an alkoxide-like serine oxygen with greater electron density. That oxygen is therefore a stronger nucleophile and can attack the electrophilic ester carbonyl carbon. The step does not create an alkene or permanently protonate the carbonyl. To solve this MCAT organic chemistry item, identify the reacting functional group, nucleophile, electrophile, and leaving group. Follow bonds: state which bond forms, which bond breaks, and how charge changes. For carbonyl chemistry, distinguish addition from acyl substitution and track the original carbonyl oxygen. For oxidation or reduction, compare carbon bonds to oxygen and hydrogen. For stereochemistry, decide whether the center is planar, chiral, or attacked from one face. In separation and spectroscopy
See full explanation + shortcut trick
Compare the quick idea with the premium step-by-step explanation and faster solving trick for this pattern.
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Shortcut used, common trap, and the fastest solving route
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
Question Locked
Unlock full topic access, detailed explanations, and premium practice support.
Upgrade to continueExplanation
Correct answer and explanation unlock after the free practice limit.
Upgrade to continueShort Explanation
PremiumShort solution is premium content.
Upgrade to continueDetailed Explanation
Correct Answer:
Method / Topic: Organic Chemistry
Deprotonation produces an alkoxide-like serine oxygen with greater electron density. That oxygen is therefore a stronger nucleophile and can attack the electrophilic ester carbonyl carbon. The step does not create an alkene or permanently protonate the carbonyl. To solve this MCAT organic chemistry item, identify the reacting functional group, nucleophile, electrophile, and leaving group. Follow bonds: state which bond forms, which bond breaks, and how charge changes. For carbonyl chemistry, distinguish addition from acyl substitution and track the original carbonyl oxygen. For oxidation or reduction, compare carbon bonds to oxygen and hydrogen. For stereochemistry, decide whether the center is planar, chiral, or attacked from one face. In separation and spectroscopy
See full explanation + shortcut trick
Use the free answer check first, then unlock the complete breakdown, shortcut path, and richer explanations for similar questions.
Keep Practicing This Pattern
Recommended Next Practice
Use these suggestions after solving the practice questions above.