Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Solve this faster with the right shortcut first
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
Correct Answer: A
Correct Answer: A
Method / Topic: Organic Chemistry
The correct option matches the required rule and the given information.
Short Explanation
Detailed Explanation
Correct Answer: A
Method / Topic: Organic Chemistry
The enolate has electron density at its alpha carbon and donates an electron pair to the electrophilic carbonyl carbon of another ethanal molecule. Therefore it functions as a carbon nucleophile. The attacked carbonyl oxygen becomes an alkoxide before protonation gives the beta-hydroxy aldehyde. This conclusion follows from electron flow, functional-group behavior, and the stated experimental conditions. For MCAT organic chemistry, first mark the nucleophile, electrophile, leaving group, and any resonance-stabilized intermediate; then track bonds rather than memorizing a product name. Check stereochemistry, charge, and carbon count before choosing an
, and interpret evidence without overclaiming. Always reconcile the proposed structure with every observation in the
See full explanation + shortcut trick
Compare the quick idea with the premium step-by-step explanation and faster solving trick for this pattern.
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Shortcut used, common trap, and the fastest solving route
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
PASSAGE 4 — ALDOL REACTION AND PURIFICATION Two molecules of ethanal react under dilute basic conditions. An enolate forms reversibly and attacks the carbonyl carbon of another ethanal molecule, initially producing 3-hydroxybutanal. Heating promotes loss of water to form an alpha,beta-unsaturated aldehyde. The reaction mixture is separated by silica-gel chromatography, using a solvent whose polarity can be gradually increased. QUESTION 10: In the first carbon–carbon bond-forming step, the enolate acts primarily as
Explanation
Correct Answer: A
Method / Topic: Organic Chemistry
The correct option matches the required rule and the given information.
Short Explanation
Detailed Explanation
Correct Answer: A
Method / Topic: Organic Chemistry
The enolate has electron density at its alpha carbon and donates an electron pair to the electrophilic carbonyl carbon of another ethanal molecule. Therefore it functions as a carbon nucleophile. The attacked carbonyl oxygen becomes an alkoxide before protonation gives the beta-hydroxy aldehyde. This conclusion follows from electron flow, functional-group behavior, and the stated experimental conditions. For MCAT organic chemistry, first mark the nucleophile, electrophile, leaving group, and any resonance-stabilized intermediate; then track bonds rather than memorizing a product name. Check stereochemistry, charge, and carbon count before choosing an
, and interpret evidence without overclaiming. Always reconcile the proposed structure with every observation in the
See full explanation + shortcut trick
Use the free answer check first, then unlock the complete breakdown, shortcut path, and richer explanations for similar questions.
Keep Practicing This Pattern
Recommended Next Practice
Use these suggestions after solving the practice questions above.