Quantitative Aptitude SSC GD, SSC quantitative aptitude Free access now

Pipes and Cisterns for SSC GD | Concepts & Practice | SSC GD Quantitative Aptitude

Build Pipes and Cisterns accuracy for SSC GD with concept clarity, key relations, exam-speed methods and approved practice.

Tailored for SSC GD Quantitative Aptitude. 4 active practice questions. Related topics: Percentage, Profit and Loss, Simple Interest.

SSC GD approach: For SSC GD, keep this topic practical and direct. The target is to recognise familiar patterns quickly and apply the shortest reliable method without creating extra working.

What to master: Master the basic rule, repeat high-frequency patterns, and practise small timed sets where the same concept appears in more than one surface form.

SSC GD focus:

Keep the method simple and dependable for SSC GD, with emphasis on fast recognition and basic exam-ready accuracy.

Attempt strategy: For SSC GD, prefer the shortest clear method, avoid over-solving, and practise recognising familiar patterns without sacrificing accuracy.

Revision path: GD revision: core rule -> easy pattern -> speed drill -> quick correction.

SSC GD exam emphasis for Pipes and Cisterns

GD emphasis: clarity, rapid recognition, direct working, and dependable accuracy.

Most important error to avoid

Typical GD loss comes from overthinking a simple pattern, skipping a basic check, or using a longer process when a direct rule would solve the question.

SSC GD Pipes and Cisterns — GD speed-and-clarity plan

Keep the working compact and visual or rule-based wherever possible. The target is fast recognition without adding unnecessary steps. For Pipes and Cisterns, concentrate on work-rate conversion, inlet and outlet direction, combined filling or emptying, and time-to-complete relationships.

How to practise this topic

Use repeated small drills built around core patterns, then add one variation at a time. Stop and correct immediately when the same mistake appears twice. A reliable drill sequence is to convert each pipe to a one-minute rate, combine signed rates, solve the required time, then verify whether the tank should be filling or emptying.

Mistakes to remove before the next set

Watch specifically for mixing filling and emptying signs, combining times directly instead of rates, and missing the net-rate direction. During review, reduce the solution to the minimum reliable steps and practise recalling those steps without notes before attempting another set.

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4 practice questions

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Learn the shortcut

Understand the fastest pattern for this topic before you attempt full MCQs.

Avoid common traps

See where students commonly lose marks so you can eliminate bad options earlier.

Solve faster in exam

Apply one practical method before attempting MCQs and cut down hesitation.

Summary Formula Tricks Mistakes Solved Example Practice FAQ

Pipes and Cisterns revision for SSC GD: understand the base rule, apply the correct formula or relation, check common traps, then practise with approved questions.

Pipes and Cisterns is a rate problem. Filling pipes contribute positive work; emptying pipes contribute negative work. Add their rates, not their times.

SSC GD focus: Solve the core method first, then use the approved practice questions on this page to build exam-speed accuracy.

Pipes and Cisterns revision rule: concept → formula/relation → one worked example → timed practice → error review.

Core concept
Key formula/relation
Common trap
Approved practice

If a pipe fills in x hours, rate = 1/x
If an outlet empties in y hours, rate = -1/y
Net time = 1 / net rate

Use an LCM-based tank capacity when the times are clean integers; it converts fractions into simple unit rates.

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Practice Questions Login for free progress tracking

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You can start learning here right away, explore formulas and tricks, and use the current limited practice flow before premium tools arrive.

Read the exact requirement before choosing a shortcut.
Keep units, signs and percentage bases consistent.
Use the final few seconds to verify direction and magnitude.

Using a memorised shortcut without checking its condition.
Skipping unit or base conversion.
Doing long arithmetic before identifying the underlying relation.

SSC GD practice example: Two pipes fill a tank in 12 hours and 18 hours. Together their rate is 1/12 + 1/18 = 5/36, so they fill the tank in 36/5 = 7.2 hours.

Two pipes fill a tank in 20 hours and 30 hours. What fraction of the tank will they fill together in 6 hours?
A pipe fills a tank in 12 hours. After it works alone for 4 hours, a second pipe that fills the tank in 18 hours is opened. How much total time is needed to fill the tank?
An inlet fills a tank in 10 hours and an outlet empties it in 15 hours. How long will the tank take to fill when both are open?

Learn the shortcut first

Shortcut before you solve

Pipes and cisterns uses time-and-work rate logic with outlet rates subtracted.

Faster solving steps

Use this 4-step method before solving to keep your thinking fast and repeatable.

Step 1 Identify relation

Spot the pattern, relationship, or core idea first.

Step 2 Apply same pattern

Use the same rule instead of re-solving from scratch.

Step 3 Eliminate wrong options

Remove confusing choices before comparing the last few.

Step 4 Confirm final answer

Pick the option that matches the shortcut most cleanly.

Practice Questions

Start with the first 10 questions free, then unlock the rest with premium

Now apply the trick on real questions

Use the shortcut above before solving these questions

Convert each pipe into a one-hour rate; filling is positive and emptying is negative.

Tip: A pipe filling a tank in 6 hours fills 1/6 of it per hour.

Step 1

Take the full tank as 1.

Step 2

One-hour filling rate = 1/6.

Rule

Net rate = total inlet rate - total outlet rate.

3-second trick

Convert every completion time into an hourly rate first.

Trap to avoid

Do not add filling times directly.

Correct answer

1/6

Thinking path

The full tank is one unit.
Six hours means one-sixth per hour.
Multiple pipes must be combined through rates.

Final answer: 1/6

Why this is fast: Rate form makes inlet and outlet problems straightforward.

Free now: first 10 questions Premium later: full solutions, advanced tricks, targeted practice

Q1 Easy

A pipe fills three-eighths of a tank in 6 hours. At the same rate, how long will it take to fill the entire tank?

Concept type: Filling and emptying rates Shortcut used: Convert each pipe into a one-hour rate; filling is positive and emptying is negative. Quick hint: A pipe filling a tank in 6 hours fills 1/6 of it per hour.

Quick idea: The pipe will fill the tank in 16 hours.

Solve

Q2 Medium

An inlet fills a tank in 10 hours and an outlet empties it in 15 hours. How long will the tank take to fill when both are open?

Quick idea: The tank will fill in 30 hours.

Solve

Q3 Hard

A pipe fills a tank in 12 hours. After it works alone for 4 hours, a second pipe that fills the tank in 18 hours is opened. How much total time is ne…

Quick idea: The total time is 8.8 hours.

Solve

Q4 Medium

Two pipes fill a tank in 20 hours and 30 hours. What fraction of the tank will they fill together in 6 hours?

Quick idea: They will fill one-half of the tank.

Solve

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