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Shortcut used: Choose the governing electricity or magnetism relation, convert prefixes to SI units, and check sign, direction, and dimensions.
Solve in 3 steps:
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
Common mistake: Do not choose an option before confirming the exact demand of the question.
Question 6
Multiple Choice Question
Question
Parallel plates have a potential difference of 600 V and a separation of 0.030 m. Neglecting edge effects, what is the electric field magnitude between the plates?
Explanation
Correct Answer: B
ANSWER
Correct Answer: B
Method / Topic: Electricity
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
Why this answer is correct
The correct option matches the required rule and the given information.
Short Explanation
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
Detailed Explanation
Question
Parallel plates have a potential difference of 600 V and a separation of 0.030 m. Neglecting edge effects, what is the electric field magnitude between the plates?
ANSWER
Correct Answer: B
Method / Topic: Electricity
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
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Question 6
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Learn + solve
Shortcut used, common trap, and the fastest solving route
Shortcut used: Choose the governing electricity or magnetism relation, convert prefixes to SI units, and check sign, direction, and dimensions.
Solve in 3 steps:
- Mark the given values and the exact target.
- Apply the relevant formula, rule, or concept.
- Check the final value against the options.
Common mistake: Do not choose an option before confirming the exact demand of the question.
Question
Parallel plates have a potential difference of 600 V and a separation of 0.030 m. Neglecting edge effects, what is the electric field magnitude between the plates?
Explanation
Correct Answer: B
ANSWER
Correct Answer: B
Method / Topic: Electricity
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
Why this answer is correct
The correct option matches the required rule and the given information.
Short Explanation
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
Detailed Explanation
Question
Parallel plates have a potential difference of 600 V and a separation of 0.030 m. Neglecting edge effects, what is the electric field magnitude between the plates?
ANSWER
Correct Answer: B
Method / Topic: Electricity
For uniform parallel-plate fields, E = |ΔV|/d = 600/0.030 = 2.0 × 10^4 V/m.
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convert prefixes to SI units
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