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MCAT Chemical and Physical Foundations General Chemistry Medium PYQ Pattern Practice
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Learn + solve

Solve this faster with the right shortcut first

Shortcut used: Identify the chemistry principle first, write the balanced equation or formula with units, then substitute. Use units and limiting cases to eliminate distractors.
Solve in 3 steps:
  1. Mark the given values and the exact target.
  2. Apply the relevant formula, rule, or concept.
  3. Check the final value against the options.
Common mistake: Do not choose an option before confirming the exact demand of the question.
Question 2 Multiple Choice Question
Question
PASSAGE 1 — ANTACID BACK-TITRATION A laboratory evaluates a 0.500 g antacid tablet whose active ingredient is calcium carbonate, CaCO3. The tablet is treated with 50.0 mL of 0.200 M HCl. Calcium carbonate reacts according to CaCO3(s) + 2H+(aq) → Ca2+(aq) + CO2(g) + H2O(l). After the reaction is complete, the remaining acid requires 20.0 mL of 0.100 M NaOH for neutralization. Assume that other tablet ingredients do not react with either acid or base. QUESTION 2: What mass of CaCO3 was present in the tablet? (Molar mass CaCO3 ≈ 100 g/mol)
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MCAT Chemical and Physical Foundations General Chemistry
95s
Question 2
Medium Marks: 1.0 PYQ Pattern Practice
Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Learn + solve

Shortcut used, common trap, and the fastest solving route

Shortcut used: Identify the chemistry principle first, write the balanced equation or formula with units, then substitute. Use units and limiting cases to eliminate distractors.
Solve in 3 steps:
  1. Mark the given values and the exact target.
  2. Apply the relevant formula, rule, or concept.
  3. Check the final value against the options.
Common mistake: Do not choose an option before confirming the exact demand of the question.
Question

PASSAGE 1 — ANTACID BACK-TITRATION A laboratory evaluates a 0.500 g antacid tablet whose active ingredient is calcium carbonate, CaCO3. The tablet is treated with 50.0 mL of 0.200 M HCl. Calcium carbonate reacts according to CaCO3(s) + 2H+(aq) → Ca2+(aq) + CO2(g) + H2O(l). After the reaction is complete, the remaining acid requires 20.0 mL of 0.100 M NaOH for neutralization. Assume that other tablet ingredients do not react with either acid or base. QUESTION 2: What mass of CaCO3 was present in the tablet? (Molar mass CaCO3 ≈ 100 g/mol)

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PYQ-style pattern Concept tagged
Identify the chemistry principle first