Time Speed Distance for SSC CGL | Concepts & Practice

Learn the shortcut

Understand the fastest pattern for this topic before you attempt full MCQs.

Avoid common traps

See where students commonly lose marks so you can eliminate bad options earlier.

Solve faster in exam

Apply one practical method before attempting MCQs and cut down hesitation.

Summary Formula Tricks Mistakes Solved Example Practice FAQ

Time Speed Distance revision for SSC CGL: understand the base rule, apply the correct formula or relation, check common traps, then practise with approved questions.

Time, Speed and Distance are linked by distance = speed × time. The most common errors come from inconsistent units or comparing average speeds incorrectly.

SSC CGL focus: Solve the core method first, then use the approved practice questions on this page to build exam-speed accuracy.

Time Speed Distance revision rule: concept → formula/relation → one worked example → timed practice → error review.

Core concept
Key formula/relation
Common trap
Approved practice

D = ST
S = D/T
T = D/S
km/h to m/s: ×5/18; m/s to km/h: ×18/5

For equal distances at speeds a and b, average speed = 2ab/(a+b).

Next Step

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SSC CGL: Apply this concept in SSC CGL-style timed practice.

Solve topic-wise questions, measure accuracy, identify weak areas, and prepare for mock tests faster with a sharper revision flow.

Topic-wise practice built around this concept
Accuracy-focused repetition before full mocks
Weak-area clarity for smarter revision
Faster transition into timed tests

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You can start learning here right away, explore formulas and tricks, and use the current limited practice flow before premium tools arrive.

Read the exact requirement before choosing a shortcut.
Keep units, signs and percentage bases consistent.
Use the final few seconds to verify direction and magnitude.

Using a memorised shortcut without checking its condition.
Skipping unit or base conversion.
Doing long arithmetic before identifying the underlying relation.

Practice example: A person travels 180 km in 3 hours and then 120 km in 2 hours. What is his average speed for the whole journey?

Solution: The average speed is 60 km/h.

A car travels 150 km at a speed of 50 km/h and returns at 75 km/h. What is the average speed for the whole journey?
A car travels 180 km at 60 km/h and returns at 90 km/h. What is the average speed for the whole journey?
A train travels 180 km in 2 hours 15 minutes. Find its average speed.

Learn the shortcut first

Shortcut before you solve

Most speed questions are easy once the units are made uniform first.

Faster solving steps

Use this 4-step method before solving to keep your thinking fast and repeatable.

Step 1 Identify relation

Spot the pattern, relationship, or core idea first.

Step 2 Apply same pattern

Use the same rule instead of re-solving from scratch.

Step 3 Eliminate wrong options

Remove confusing choices before comparing the last few.

Step 4 Confirm final answer

Pick the option that matches the shortcut most cleanly.

Practice Questions

Start with the first 10 questions free, then unlock the rest with premium

Now apply the trick on real questions

Use the shortcut above before solving these questions

Use S = D / T and convert units before solving.

Tip: To change km/h into m/s, multiply by 5/18. To change m/s into km/h, multiply by 18/5.

Step 1

Speed = Distance / Time.

Step 2

120 / 2 = 60 km/h.

Rule

Speed = Distance / Time, Distance = Speed x Time, Time = Distance / Speed.

3-second trick

First check the units, then apply the basic formula.

Trap to avoid

Do not mix metres and kilometres or seconds and hours in one formula.

Correct answer

60 km/h

Thinking path

Distance is 120 km.
Time is 2 hours.
So speed is 60 km/h.

Final answer: 60 km/h

Why this is fast: The direct formula works instantly when units are consistent.

Free now: first 10 questions Premium later: full solutions, advanced tricks, targeted practice

Q1 Hard

A man walks at 5 km/h and reaches his destination 24 minutes late. At 6 km/h he reaches 6 minutes early. Find the distance.