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- Check units.
- Convert if needed.
- Apply S = D/T, D = S x T, or T = D/S.
Correct Answer: A
Correct Answer: A
Method / Topic: Time Speed Distance
The answer uses consistent units in the speed-distance-time relation.
Short Explanation
Detailed Explanation
Correct Answer: A
Method / Topic: Time Speed Distance
<table cellspacing="0" style="border-collapse:collapse; height:20px; width:85px">
<tbody>
<tr>
<td style="border-bottom:1px solid #44b3e1; border-left:none; border-right:none; border-top:1px solid #44b3e1; height:20px; vertical-align:top; white-space:normal; width:85px"><span style="color:#000000">The difference in travel times is 24+6=30 minutes=1/2 hour. For distance d, d/5−d/6=d/30. Setting d/30=1/2 gives d=15 km. The late and early times are added because they lie on opposite sides of the scheduled arrival time. The calculation is checked against the conditions in the
. A useful final check is to substitute the
s involving signs, denominators, amount versus interest, and distance versus speed.</span></td>
</tr>
</tbody>
</table>
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Learn + Solve: Shortcut, Trap & Fast Route Click to view shortcut, steps, and common mistake
Shortcut used, common trap, and the fastest solving route
- Check units.
- Convert if needed.
- Apply S = D/T, D = S x T, or T = D/S.
A man walks at 5 km/h and reaches his destination 24 minutes late. At 6 km/h he reaches 6 minutes early. Find the distance.
Explanation
Correct Answer: A
Method / Topic: Time Speed Distance
The answer uses consistent units in the speed-distance-time relation.
Short Explanation
Detailed Explanation
Correct Answer: A
Method / Topic: Time Speed Distance
<table cellspacing="0" style="border-collapse:collapse; height:20px; width:85px">
<tbody>
<tr>
<td style="border-bottom:1px solid #44b3e1; border-left:none; border-right:none; border-top:1px solid #44b3e1; height:20px; vertical-align:top; white-space:normal; width:85px"><span style="color:#000000">The difference in travel times is 24+6=30 minutes=1/2 hour. For distance d, d/5−d/6=d/30. Setting d/30=1/2 gives d=15 km. The late and early times are added because they lie on opposite sides of the scheduled arrival time. The calculation is checked against the conditions in the
. A useful final check is to substitute the
s involving signs, denominators, amount versus interest, and distance versus speed.</span></td>
</tr>
</tbody>
</table>
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